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[Design View / Design Solution]
Drive Piezoelectric Actuators With Fast, High-Power Op Amps
Think you can't drive your actuator at 80 kHz with 300-V p-p signals using MOSFET IC op amps? Then try out this bridge configuration.

Sam Robinson  |   ED Online ID #11302  |   November 7, 2005


In the last 15 years, high-speed piezo electric actuators have become less expensive to manufacture. Consequently, they find themselves as a favorite design choice for a growing number of applications.

Piezoelectric actuators made their initial entry in medical devices, including surgical tools and ultrasonic testing in the late 1980s. It was for good reason. Piezoelectric actuators are the fastestresponding positioning element available with microsecond time constants. They also can produce motions in subnanometer increments. So, it's no surprise to see a dramatic rise in the number of companies designing products that employ these devices.

Piezoelectric actuators require highvoltage drivers that can deliver hundreds of volts, peak-to-peak. In addition, because a typical actuator looks virtually like a pure capacitance to the driving amplifier, nearly all power dissipation becomes the burden of the driving amplifier.

A quick look through the abundance of high-speed, small-signal op amps will disclose many amplifiers with bandwidths in the hundreds of megahertz. But to combine that speed with more than 12 V, as you must if you're planning to drive a highspeed piezoelectric device, the choices of suitable amplifiers shrink pretty fast. Moreover, choosing a design based upon a MOSFET monolithic amplifier has compelling benefits.

The piezoelectric actuator circuit in the example presented here requires a 300-V p-p source at 80 kHz. It will drive our actuator, which can be represented by a 1-nF capacitance in series with a 1-Ω resistance (Fig. 1).

A LOOK AT THE OPTIONS We evaluated several alternatives for our application before deciding on the best approach to drive a piezoelectric actuator:

  • Single amplifier: Cost is the issue with this option. Because a piezoelectric actuator will require a swing between +150 V and –150 V, the only device on the market that meets this requirement at a frequency of 80 kHz is going to be a hybrid, which will price out at over $100 each.
  • Small-signal amplifier with level shifting: A design that begins with a small-signal amplifier, followed by level shifting, means configuring a design from scratch with a large number of discretes. In this case, the nonrecurringengineering effort will be large, and the design time will be long and costly.
  • High-voltage, high-speed, low-current MOSFET op-amp IC: The monolithic PA78, which we chose for this design, uses a class A/B driver stage to drive output MOSFETs and an innovative input stage to achieve very high slew rates— without the high quiescent currents of traditional op-amp designs. Also, this design will require two PA78s. And because this amplifier is an IC design, it will cost approximately $15 each. That's a considerable savings vis-à-vis the hybrid at over $100.

As depicted in Figure 1, we've configured two PA78s in a bridge circuit.1 In this configuration, the amplifiers supply an output-voltage swing twice that of a single op amp. This configuration doubles the slew rate. Any nonlinearities become symmetrical, reducing secondharmonic distortion compared to a singleamplifier circuit.

The sinusoidal source applies 15 V p-p at 80 kHz to drive the amplifier pair, which, in turn, drives the piezoelectric actuator. In our case, we shall assume that the piezoelectric actuator will exhibit an equivalent impedance of a 1-nF capacitor in series with a 1-Ω resistor, as shown.

A FLOATING LOAD In our application, the load is floating. In other words, it's not ground-connected at all. When the left output VOUTA swings from 10 to 160 V (Fig. 2a) and the right output VOUTB descends from 160 V to 10 V (Fig. 2b), a voltage swing of 300 V (–150 V to +150 V) develops across the load (Fig. 2c).

The outputs of the two amplifiers are now out of phase. The overall gain of the bridge-configured PA78s is +20, so that 300 V p-p is delivered to the piezoelectric actuator, as required. The feedback circuit comprising resistors R3 and R4 center both of the PA78 modules' outputs around 85 V. As shown in Figure 1, a dual-source, asymmetric power supply delivers +175 V and –5 V to the two amplifier modules.2

ESTABLISH +VS, –VS HEADROOM The values of +VS and –VS must be carefully chosen to ensure sufficient headroom during the positive and negative excursions of both VOUTA and VOUTB. The output VOUTA – VOUTB will swing from +150 V to –150 V. But it's the amplifier's common-mode input range (CMR) positive and negative values (specified in the PA78 data sheet) that play a significant role in governing the values of +VS and –VS in this asymmetrical sourcing arrangement.

In the case of the PA78, the specified value of the CMR negative is –VS + 3 V. This means the input should approach the negative rail no closer than 3 V. Therefore, by choosing –VS equal to –5 V, both VOUTA and VOUTB (having negative excursions to 10 V) will approach the negative rail no closer than 15 V. With the CMR positive, the value is +VS – 2 V. This means that the most positive-going excursion of both VOUTA and VOUTB must stay at least 2 V below +VS.

A second issue with regard to the +VS rail is the voltage drop at the output when the modules are delivering peak current. In this application, the peak current is approximately 75 mA. A graph in the PA78 data sheet called "Output Voltage Swing" says that if you're driving this much current, you will lose approximately 8 V. The sum of the two, 2 V and 8 V, is 10 V, which says the +VS must be at least 10 V above our maximum voltage swing of 150 V. Choosing a +VS of 175 V means an additional headroom margin of 15 V.

With any piezoelectric actuator circuit, it's essential to prevent signals from inadvertently feeding back to the amplifier. A piezo transducer can convert mechanical into electrical energy just as easily as going from electrical to mechanical. So if something were to bump the transducer, it may create lots of energy that would travel backwards into the output of the amplifier. Of course, that could be rather destructive. Yet simply connecting several ultra-fast MUR160 diodes (CR1 to CR4) from the output of each amplifier to its corresponding power-supply rails will protect each amplifier.


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