[Ideas For Design]
Germanium Dual-Boost Starts At 260 mV
Clayton B. Grantham
ED Online ID #15420
May 10, 2007
Copyright © 2006 Penton Media, Inc., All rights reserved. Printing of this document is for personal use only.
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No matter what portable power
source you use, the lower the starting
voltage your circuitry operates at, the
better. A lower startup voltage also maximizes runtime. Furthermore, to completely discharge the power source, circuitry must run on ever-lower voltages
and currents.
Existing boost circuits can start up
and drain a power source down to 1 V,
but that still leaves too much unusable
energy in a battery. Other power sources,
like solar cells or micro-turbines, need
circuitry to start up at much less than 1 V. For instance, a single solar cell has a
full-sun output of only 0.58 V.
The circuit in Figure 1 targets this
problem. It performs a dual-inductor
step-up conversion at a startup voltage
as low as 260 mV. An inductive dc-dc
boost circuit outputs a higher voltage
than its input. A germanium-transistor
balanced-boost circuit is simple, using
only two NPN transistors, but it unconditionally starts at a very low voltage. Previous silicon-transistor boost circuits required approximately a volt to start and
many more components.
The circuit operates like a free-running
multi-vibrator. The repetitive cycle starts
with VIN slightly above Q2's VBE. This creates a positive Q2 base current (IB = (VIN
VBE)/R1) flowing through L1, and Q2
turns on, which switches inductor L2 to
ground. Q1 is off, and L1's current flow is
very small. D1 and D2 are off. Energy
stored within L2's magnetic field builds as
L2's current rises with a positive di/dt. As
this current rises, it also flows through
Q2's RSAT. Q2's collector voltage becomes
sufficiently large to turn on Q1.
R2 connects Q1's base voltage to Q2's
collector. R2 also limits Q1's base current.
With Q1 turning on, the previous base
drive to Q2 is now shunted to ground, and
Q2 turns off. Switching off Q2 allows L2's
flyback energy to forward-bias D2 and
flow into the load (R3) as L1's magnetic
field collapses. D1 remains off. With L2
discharged, D2 turns back off. L1's magnetic field has been building as L1's current rises with a positive di/dt. This current flows through Q1's RSAT. Q1's collector voltage becomes sufficiently large to
turn on Q2.
Q2's base voltage is connected to
Q1's collector by R1, which also limits
Q2's base current. With Q2 turning on,
the previous base drive to Q1 is now
shunted to ground, and Q1 turns off.
Switching off Q1 enables L1's flyback
energy to forward-bias D1 and flow into
the load (R3) as L1's magnetic field collapses. D2 remains off. With L1 discharged, D1 turns off.
This self-oscillating action repeats until
the battery voltage falls below Q1's or
Q2's VBE. As the input voltage increases,
the stored energy in L1 and L2 increases,
and thus the average voltage on R3
increases.
The inductance of L1 and L2, the RSAT
of Q1 and Q2, and the switching characteristics of Q1 and Q2 determine the period and duty cycle of the self-oscillation.
The circuit can be optimized for a specific
load and input source with adjustments
to both L and R. As shown, the typical switching frequency at the output is 88
kHz (with VIN = 0.5 V). Inductances of 100
H would yield 60 kHz, and 39 µH would
give 152 kHz.
The advantage of this dual-boost configuration versus a single-ended boost
configuration is that the output ripple
contains lower noise and the input
source is not off during flyback. For a
solar cell or micro-turbine input, an off
cycle is less than optimal.
Figure 2 shows the circuit's input/output transfer characteristics. The voltage
gain (step-up action) is shown for several
resistive loads. Note that this boost circuit
is open-loop, so it doesn't regulate the
output voltage or current. Some applications, however, don't require regulation.
For example, this circuit could drive an
LM2901 quad comparator and LM2902
quad op amp directly. Other applications
(logic circuits) require only limited upper
voltage regulation that could be accomplished with a shunt regulator or zener
on the output.
But for the highest efficiency, use this
boost circuit only to temporarily power up
a full-feature, high-efficiency switched-mode power-supply (SMPS) IC, connecting the transient boost's output to the IC's
low-current VCC input. Once the IC starts
up, the boost circuit can be turned off.
One way to do that would be to substitute
P-channel JFETs (NTE326) for R1 and R2,
then pull their gates above the input voltage (VIN + 1.2 V).
Also, the input voltage is limited to 2.0 V. A larger input voltage will cause excessive current to flow in the base of Q1 and
Q2, which are connected through R1, R2, L1, and L2 directly to VIN.
A slightly different transfer characteristic results if this circuit drives a white
LED rather than a resistive load. A white
LED typically requires 3.6 V at 20 mA for
proper operation—thus, the need for a boost circuit if an alkaline battery is the
power source. An LED's brightness
depends directly on the average flyback
current flow through D1 and D2.
Nominal LED current measurements
with an alkaline battery were 3 mA at 0.53 V, 14 mA at 0.95 V, 26 mA at 1.19
V, 31 mA at 1.27 V, and 50 mA at 1.53 V.
Those results were with Coilcraft
DO1608C-683 inductors and a Nichia
BSPW500BS LED.
With many portable electronics (toys,
PDAs, etc.), you must discard a single
alkaline as "dead" when the cell voltage is about a volt. But such batteries
can provide LED illumination with this
circuit, as well as a more complete battery discharge.
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