View this week's entry ad »
Part Inventory
powered by:
Part Finder
Go
powered by:
  • Quick Poll
What Social Networking site do you use the most?



VOTE VIEW RESULTS
Previous Polls
Hotspots » Analog & Mixed SignalPowerEmbedded

Premium Content

Editors' Picks

Featured Industry Resources

Wide-Range Pulse-Width Modulator Uses 555 Timer

Highlights

  • The circuit's duty factor is adjustable from 1% to 99%
  • Applications include speed control of electric motors
  • The circuit can also be used to control lighting

By Henry Santana

September 15, 2005

Print
Reprints Comment Subscribe

Simply adding a diode and potentiometer to a 555 timer operating in the asynchronous mode yields a pulsewidth modulator (PWM) with a duty factor adjustable from 1% to 99% (Fig. 1). Applications would include speed control of electric motors where the switching drive can be power efficient.

The output of this circuit could drive a MOSFET to control the current through the motor, resulting in smooth control of the motor speed at efficiencies on the order of 90%. This also applies to lighting control, where the light intensity can be controlled efficiently.

Another application is in switching power supplies, where the PWM adjustment permits a variable output voltage. Feedback to the VC terminal of the 555 timer (pin 5) can be used to regulate the voltage. An output voltage in excess of the regulation threshold would force an early termination of the PWM signal on a cycle-by-cycle basis by pulling down on the VC terminal to maintain the output voltage.

A microprocessor could adjust the PWM directly through a digital potentiometer to control motor speed, light intensity, or power-supply output voltage.

For the duty factor (DF):

see equation

where:

see equation

and a is the ratio of the resistance between terminals 2 and 1 to the resistance between terminals 3 and 1 of R2. Choose R3 = R1, and R2 = 100 X R1. This will allow a duty factor of 1% to 99%.

As mentioned, a digital potentiometer can be substituted for R2. Limited current flow is the main constraint in using a digital potentiometer in this application. For a 100-kO digital potentiometer, R1 and R3 would be 1 kO, resulting in a peak current flow of 5 mA.

A standard diode may be used for D at reduced linearity. For an ideal diode, k = 0.693 and:

see equation

resulting a linear relationship between DF and a. Figure 2 shows the VOUT waveform as a is varied.

See figure 2

Average ( Ratings):
Filed Under:

Check for price and availability on Source ESB:

Go
powered by  

Related Products

You must log on before posting a comment.

Are you a new visitor? Register Now

Acceptable Use Policy

Sponsored Links