• Channels
Part Inventory
Go
 
powered by:

 
  • Quick Poll
What Social Networking site do you use the most?



VOTE VIEW RESULTS
Previous Polls

Premium Content

New Signal Chain Technical Papers from Texas Instruments:

 

 

 

Pulse-Width Modulator Features Versatile Operating Parameters


Ken Yang

March 01, 2004

Print
Reprints Comment Subscribe

Included among the many applications for pulse-width modulation (PWM) are voltage regulation, power-level control, and fan-speed control. A PWM circuit for such systems can be implemented with three op amps on a single quad-op-amp chip (Fig. 1).

Because op amps are used for the modulator, it's suited for a wide variety of applications. For example, low-power op amps can be used in a low-power system, and high-frequency op amps can be used for a high-frequency PWM. The circuit in Figure 1 also generates a triangular wave.

The circuit consists of a triangular-wave generator (U1a and U1b) and a comparator (U1c). U1a is configured as an integrator (or de-integrator) and U1b as a comparator with hysteresis. At power-up, the comparator's output voltage is assumed to be zero.

U1a's noninverting input is biased at VCC/2. A virtual connection between the inverting and noninverting inputs allows a constant current through R equal to I = VCC/2R, which charges capacitor C. Thus, the U1A integrator output increases linearly with time. When it reaches 0.75 VCC, the comparator output (U1b) changes to its maximum output voltage (VCC). At that point, the integrator begins to de-integrate, causing the output voltage to decrease linearly. When it reaches 0.25 VCC, the comparator output voltage changes to zero, and the cycle repeats. Thus, the integrator output is a triangular wave that swings between the levels of 0.25 VCC and 0.75 VCC.

U1c compares the triangular wave against the dc level VIN. Its output is a square wave, with a duty cycle that varies from 0 to 100% as VIN varies from 0.25 VCC to 0.75 VCC (Fig. 2). Frequency is determined by R, C, R1, and R2:

f = R2/(4RCR1)

where R2 > R1.

The ratio of R2 and R1 affects the operating frequency and the amplitude of the triangular wave. Given that VTH is the triangular wave's maximum voltage and VTL is its minimum voltage, the amplitude swing is:

VTH = VCC(R1 + R2)/2R2, and

VTL = VCC(R2 − R1)/2R2,

where R2 > R1. Therefore:

VTH − VTL = (R1/R2)VCC (R2 > R1).

The triangular wave's peak-to-peak voltage is centered at the VCC/2 bias voltage generated by R3 and R4. With the circuit configuration shown, the PWM operates on a single supply. Use micropower op amps and larger resistors (R and R1 to R4) for low-power applications and high-frequency op amps for higher-frequency applications. (The quad op amp shown comes in a single package.)

Average (0 Ratings):

Subscribe
Subscribe to Electronic Design and start receiving more articles like this one
Filed Under:

Check for price and availability on Source ESB:

Go
powered by  
    There are no comments to display. Be the first one!
You must log on before posting a comment.

Are you a new visitor? Register Here
Acceptable Use Policy

Sponsored Links